If it's not what You are looking for type in the equation solver your own equation and let us solve it.
16b^2+24b+5=0
a = 16; b = 24; c = +5;
Δ = b2-4ac
Δ = 242-4·16·5
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-16}{2*16}=\frac{-40}{32} =-1+1/4 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+16}{2*16}=\frac{-8}{32} =-1/4 $
| 3+z/3=18 | | 16=81x^2 | | 21+5m=7(5m+3) | | 7-8p-3=-12 | | p2+8p=-12 | | 6-x-4=2 | | x(x+1)=2x+20 | | 2(8x+3)-4x=3(4x+6)-23 | | 7^4=7^6-2x | | 5x-6+4=13 | | r/5+45=81 | | 2x+46=3x+1 | | x+7/14=1−3/2x | | 4/9d=-4 | | 1/2y+4=7 | | 3^3x-1=24 | | 3n-2n4=n=7n4-2 | | 10−13y=36 | | 3(3m/4-1)+m/5=42-m/4 | | 10x−13=36 | | 14n+6=202 | | x+22+2x-7=90 | | -21=-3+2a+4a | | X^2+-5x+-8=0 | | X2+-5x+8=0 | | 11a-4=18 | | 2(3+4x)-5=33 | | x^2+12-48x=0 | | 6c=126 | | 6c+c=126 | | 7=-6+6y+7 | | 6c+c=127 |